My Special Lovable Bunny Friend

Concept

We use the position and orientation of our loveable bunny friend to play games. This allows children to keep playing with their dolls even when on the computer by using their doll as a controller of sorts.We also demonstrate how the orientation and position of a doll can be accurately tracked through accelerometer, gyroscope and magnetometer information.

Target

Little children who play with dolls have to unfortunately put their toys down when accessing technology. With this, we enable children to not put down their toys even when on the computer. Furthermore, this allows them to bring their dolls into various realities and worlds as they play different games. The target audience is children.

Technical System

The YEI 3-Space sensor constantly takes down information on its three sensors. The accelerometer, magnetometer, and gyroscope. We use serial communication to read the data and process it into position and orientation information on our loveable bunny. The sensor is hidden inside the bunny along with the microcontroller or bluetooth chip. These then send information to the computer or display where a game is visually shown and can be played through the orientation and position of the bunny.

The game we developed is a 3-D version of cube runner where a bunny can move in different directions depending on the orientation it is facing. The objective is to dodge cubes for as long as possible and it is built in Unity.

Specs

3-Space Sensor - $124 - ordered from eBay

Teensy - $24 - Teensy website

Arduino Kit - $85 - from the arduino website

Bluetooth Chip - $10 - eBay

Manufacturing Techniques

The only advanced technique we will use aside from using a breadboard to hook up wires together includes soldering pieces onto the sensor to establish a more stable connection.

Problems

Sensor was broken.

Unsteady connection - needs to be soldered.

None of the code snippets found and modified seem to work.

Solution - we will order another sensor; one that has a USB connection built in.

Division of Labor

Kevin - Assisted in building Unity game

         - Contributed to game design

Simon - Built game to be played via bunny in Unity

          - motivational support

Zach - getting the sensor data to work properly and connect with Unity

        - contributing to game design

Homework 5


Part 1
https://drive.google.com/file/d/0B8ZGdT5f3eJka0gtdFkzZkY5cVk/view?usp=sharing

What language is Processing based on?

Java

In your own words, what is the difference between a global and a local variable?

A global variable can be accessed or modified anywhere in code. Local variables exist only within that scope and cannot be accessed through code outside that scope.

What data type does the draw() function return when it is called?

void. no return necessary.

In your own words, explain in detail what the code below the “//keep the circle in bounds” comment does

 if the top of the circle is above the top boundary or bottom of the circle is below the bottom boundary. reverse Y velocity.

Part 2
https://drive.google.com/file/d/0B8ZGdT5f3eJkVnJodEFnWUEzcXc/view?usp=sharing


Part 3
https://drive.google.com/file/d/0B8ZGdT5f3eJkVkFnTXpmZmgzdXM/view?usp=sharing   etchasketch

Homework 3

Homework 3

Part 1)
https://drive.google.com/file/d/0B8ZGdT5f3eJkc0VOSkVHZy1XQWc/view?usp=sharing
This tech can allow wheel chairs to recognize when a person is sitting properly on the seat or has fallen off and may be in danger.
It can also be used to measure the strength of a persons pulse to recognize when it is weaker than normal based on fluctuations read on the force sensitive resistor.

Part 2)
https://drive.google.com/file/d/0B8ZGdT5f3eJkNHhfZWJydVZzMzQ/view?usp=sharing

Voltage is not divided here because max voltage is only 2 Volts.

The designs using this sensor cannot take part in any quick reactive physical computing. Rather, it is more useful at making slow gradual adjustments, like adjusting flame in an oven based on the temperature.

One way to use this is to adjust light in a sunbathing capsule based on temperature.
Another way is to use these in fire detectors. When temperature hits a certain level that is dangerous, the fire alarm should sound.

Part 3)
https://drive.google.com/file/d/0B8ZGdT5f3eJkdWxMcjRJNi15bWM/view?usp=sharing

Current going through the switch LED is limited by a 10kOhm resistor whereas the other LED is limited only by a 560Ohm resistor.

Current through the switch LED is 5/10000=.0005 Amps whereas current through the other LED is 5/560=.009 Amps

Part 4)
https://drive.google.com/file/d/0B8ZGdT5f3eJkUlJ1TFFadmNLXzA/view?usp=sharing

Sensitivity is much greater when the potentiometer resistance is turned to a minimum.

Part 5)
https://drive.google.com/file/d/0B8ZGdT5f3eJkOC0wYUZDcWdnMEE/view?usp=sharing

https://drive.google.com/file/d/0B8ZGdT5f3eJkb3hCUDlUdHdDaEE/view?usp=sharing

Physical Computing Homework 2

Homework assignment 2

Part 1
https://drive.google.com/file/d/0B8ZGdT5f3eJkczBsSkswcXNHUkk/view?usp=sharing

Part 2
https://drive.google.com/file/d/0B8ZGdT5f3eJkR1hzeFpNWFVNN28/view?usp=sharing
1) I would move the switch past the junction point along the 560 ohm resistor.
Wo when the switch is open, current can only flow through the 10kiloOhm resistor.
When the switch is closed, most of the current will flow through the 560 ohm resistor due to the significantly lower resistance.
Arguably no current goes through the 10kiloOhm resistor.

Part 3
https://drive.google.com/file/d/0B8ZGdT5f3eJkTklKbS1yX0QtUlk/view?usp=sharing
1) 5 Volts, effectively no resistance means all of the voltage is left going back into the pin.
2) 0 Volts, all voltage is used up in the resistor.
3) 5kOhms because this evens out the current going into both sides, and since 10kOhms takes up all the voltage, 5kOhms will take up half as much voltage.
4) Because the LED faces the full force of voltage coming from pin5 since the resistor is located after.
In this situation, 5V / 4 results in a maximum voltage of 1.2V that will protect the LED from blowing.

Part 4
https://drive.google.com/file/d/0B8ZGdT5f3eJkQ3o2cmdPMk1PbEE/view?usp=sharing
1) No, becuase the speaker has 8Ohms of resistance which limits the current and prevents a short circuit.
2) More current.
3) Yes.

Part 5
https://drive.google.com/file/d/0B8ZGdT5f3eJkd3RlQ3ZKUzBFc3M/view?usp=sharing
1) Switch the locations of the 10kOhm resistor and photoresistor. When light increases, resistance increases on the path going to ground, which means more current flows into the pin.

Instrument:

By the definition of interactivity, there is a cycle of exchange between me, the controller and the unstruments base note. As the instrument continues to play arpeggios, I adjust my input so that it adjusts it's output.

Critique: No cover. could be better on that aspect.

https://drive.google.com/file/d/0B8ZGdT5f3eJkNjdmaFVtR1E3OEE/view?usp=sharing

Week 1 Physical Computing: Basics
by Simon Zhang

This week we worked with basic electronics using resistors, capacitors, potentiometers, LED's and switches.

Simple LED Circuit
https://drive.google.com/open?id=0B8ZGdT5f3eJkNDZsc2I2ZWVHdnc&authuser=1

1) What is the purpose of the resistor?

Protect the LED from being fried. To use up some of the voltage and to limit current so that wires do not overheat.

2) Using Ohm’s Law (V=IR), what is the current running through this circuit?

5/560 = .009 Amps3) Using Ohm’s Law again, calculate the resistor value you would have to use in order to have only 15mA of current in this circuit?

5/.015 = 333.33333~ Ohms

4) Assuming the LED drops 2.2V of voltage, how much voltage is dropped by the resistor?

5-2.2 = 2.8Volts

LED Circuit with Switch

https://drive.google.com/open?id=0B8ZGdT5f3eJkSEhJUUpEd28yQ2M&authuser=1

1) Looking at the schematic diagram, if you moved the switch so that it was connected between the resistor and the LED, how would the circuit’s behavior change?

Nothing would Change. The switch in any location on this circuit acts to open and close the circuit.

2) Looking at the schematic diagram, if you moved the switch so that it was connected between the LED and ground, , how would the circuit’s behavior change?

Still Nothing would change. For the same reason as before.

Simple LED Circuit with Potentiometer

https://drive.google.com/open?id=0B8ZGdT5f3eJkWi1NYW5wQ1NHbkU&authuser=1

1) Why is the 560Ω resistor necessary?

Once again, this is to limit the current and reduce the maximum voltage allowed to go into the LED.

If the Potentiometer were turned so that resistance towards the LED were 0, then we depend on the 560 Ohm resistor to keep the LED from frying.

2) How much current is flowing through the circuit when the 10kΩ potentiometer is turned all the way up (offering the maximum resistance)?

5/(10000+560) = .5 milliAmperes

This effectively makes the LED go out since there is too much resistance.

3) What other types of variable resistors do you know about (name at least 4)?

Volume control, Brightness control, Photoresistors.

Dueling LEDs circuit with potentiometer

https://drive.google.com/open?id=0B8ZGdT5f3eJkQ2VGeEc1ZVNKaFE&authuser=1

1) Give a quick (1-2 sentences) explanation of why this circuit behaves the way it does. Include an explanation for how the current going through each LED is affected by a single turn of the potentiometer

The potentiometer just varies the resistance going towards both sides of the output wires. By turning it all the way one way, one directions recieves all 10kOhms of resistance and the other side has no resistance. By turning the potentiomter back and forth, the current going to both LED's varies because their currents vary. If turned all the way one way, one of the LED's would receive all remaining voltage and the other LED would have no current going through it because resistance is too high.

Capacitor Charging

https://drive.google.com/open?id=0B8ZGdT5f3eJkYUNzRURjX243VUU&authuser=1

1) How does adding a 2.2kΩ resistor between the pushbutton and the capacitor affect the capacitor’s charging behavior?

The charging behavior would be slower, and the initial current with which the capacitor is charged would start at a lower value.

Capacitor Discharging with LED delay

https://drive.google.com/open?id=0B8ZGdT5f3eJkTDZDZ0hSTFd0QWc&authuser=1

1) Looking at the circuit schematic diagram, why does the capacitor discharge up through the LED part of the circuit, and not directly from the capacitor down to ground?

Charge is built up on one side of the capacitor and can only leave through that side. In our theory, positive charge builds up on the north side of our capacitor and can only escape by moving up, turning right, and going through the LED. That way, it can travel to ground.

Test Post

Hi.